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JEE Main 2019 (10 Jan, Shift 2) · Graphs of Motion

Graphs of Motion question from JEE Main 2019 (10 Jan, Shift 2)

Q29JEE Main 2019 · 10 JAN · SHIFT 2Medium

Graphs of Motion

A particle starts from the origin at time t = 0 and moves along the positive x-axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time t = 5s?

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Answer: (b)

Starting at the origin, position = area under the $v$ - $t$ graph.
0-2 s: $\frac{1}{2}\times 2\times 2 = 2$ ; 2-4 s: $2\times 2 = 4$ ; 4-5 s: $3\times 1 = 3$
$x(5) = 2 + 4 + 3 = 9\text{ m}$ . So the answer is (b).

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