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JEE Main 2023 (6 Apr, Shift 2) · Equations of Kinematics

Equations of Kinematics question from JEE Main 2023 (6 Apr, Shift 2)

Q15JEE Main 2023 · 6 APR · SHIFT 2Easy

Equations of Kinematics

A particle starts with an initial velocity of 10.0 ms−110.0\text{ ms}^{-1} along xx-direction and accelerates uniformly at the rate of 2.0 ms−22.0\text{ ms}^{-2}. The time taken by the particle to reach the velocity of 60.0 ms−160.0\text{ ms}^{-1} is __________.

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Answer: (d)

  1. v=u+atv = u + at
  2. 60=10+2t60 = 10 + 2t
  3. t=25 st = 25\text{ s}. So the answer is (d).
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