A pendulum bob has a speed 4 m/s at its lowest position. The pendulum is 1 m long. When the length of the string makes an angle of 60° with the vertical, the speed of the bob at that position is (acceleration due to gravity, g = 10 m/s², cos 60° = 0.5) (a) 6 m/s (b) √(3) m/s (c) √(6) m/s (d) 3 m/s

Answer: (c). Energy: v² = u² - 2gL(1 - cos 60°) v² = 16 - 2(10)(1)(0.5) = 6 So the answer is (c) √(6) m/s.

A pendulum bob has a speed 4 m/s at its lowest position. The pendulum… | MHT CET 2025 (21 Apr, Shift 2)

Q6MHT CET 2025 · 21 APR · SHIFT 2Easy

Vertical Circle: Speed & Tension

A pendulum bob has a speed $4\text{ m/s}$ at its lowest position. The pendulum is 1 m long. When the length of the string makes an angle of $60^\circ$ with the vertical, the speed of the bob at that position is (acceleration due to gravity, $g = 10\text{ m/s}^2, \cos 60^\circ = 0.5$ )

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Answer: (c)

Energy: $v^2 = u^2 - 2gL(1 - \cos 60^\circ)$
$v^2 = 16 - 2(10)(1)(0.5) = 6$
So the answer is (c) $\sqrt{6}\text{ m/s}$ .

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Vertical Circle: Speed & Tension question from MHT CET 2025 (21 Apr, Shift 2)

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