Physics Circle home Student Login

Home›Chapters›Oscillations PYQs›Velocity & Acceleration in SHM›Question 66

NEET 2018 · Velocity & Acceleration in SHM

Velocity & Acceleration in SHM question from NEET 2018

Q66NEET 2018Easy

Velocity & Acceleration in SHM

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m s–2 at a distance of 5 m from the mean position. The time period of oscillation is

Show answer and solution

Answer: (b)

  1. ∣a∣=ω2x⇒ω2=205=4|a| = \omega^2 x \Rightarrow \omega^2 = \frac{20}{5} = 4, ω=2\omega = 2 rad/s
  2. T=2πω=2π2=πT = \frac{2\pi}{\omega} = \frac{2\pi}{2} = \pi s
  3. So the answer is (b) π\pi s.
Report a mistake

More questions on Velocity & Acceleration in SHM