Student Login

Home›Chapters›Wave Motion PYQs›Doppler Effect›Question 5

MHT CET 2026 (16 Apr, Shift 2) · Doppler Effect

Doppler Effect question from MHT CET 2026 (16 Apr, Shift 2)

Q5MHT CET 2026 · 16 APR · SHIFT 2Easy

Doppler Effect

A person observes two moving trains. 'A' reaching the station and 'B' leaving the station with equal speed of 30m/s. If both trains emit sounds with frequency 300 Hz, (speed of sound = 330 m/s) difference of frequencies heard by the person will be

Show answer and solution

Answer: (c)

Train A approaching: $f_A = 300 \times \frac{330}{330 - 30} = 330$ Hz.
Train B receding: $f_B = 300 \times \frac{330}{330 + 30} = 275$ Hz.
Difference $= 330 - 275 = 55$ Hz. So the answer is (c) $55$ Hz.

Report a mistake

More questions on Doppler Effect

A source of sound is moving towards a stationary observer with velocity ' VS ' and then…MHT CET 2026 (11 Apr, Shift 2)
When the observer moves towards a stationary source with velocity ' V₁ ', the apparent…MHT CET 2026 (16 Apr, Shift 1)
Two sirens situated one km apart are producing sound of frequency 330 Hz. The observer…MHT CET 2026 (13 May, Shift 2)
At what speed should a source of sound move so that the observer finds the apparent…MHT CET 2025 (25 Apr, Shift 2)
A sound source is moving towards a stationary observer with (1/10) th the speed of sound…MHT CET 2025 (25 Apr, Shift 1)
When source of sound moves towards a stationary observer, the apparent frequency heard by…MHT CET 2025 (19 Apr, Shift 1)
An observer moves towards a stationary source of sound with a velocity of one fifth of…MHT CET 2025 (23 Apr, Shift 1)
A person observes two moving trains. First reaching the station and another leaves the…MHT CET 2025 (5 May, Shift 2)