Physics Circle home Student Login

Home›Chapters›Work, Energy and Power PYQs›Work by a Variable Force›Question 14

JEE Main 2020 (4 Sep, Shift 2) · Work by a Variable Force

Work by a Variable Force question from JEE Main 2020 (4 Sep, Shift 2)

Q14JEE Main 2020 · 4 SEP · SHIFT 2Medium

Work by a Variable Force

A person pushes a box on a rough horizontal platform surface. He applies a force of 200 N over a distance of 15 m. Thereafter, he gets progressively tired and his applied force reduces linearly with distance to 100 N. The total distance through which the box has been moved is 30 m. What is the work done by the person during the total movement of the box?

Show answer and solution

Answer: (b)

  1. Work = area under the FF-xx graph.
  2. First 15 m (constant 200 N): W1=200×15=3000 JW_1 = 200 \times 15 = 3000\text{ J}
  3. Next 15 m (200 N falling linearly to 100 N, trapezium): W2=12(200+100)(15)=2250 JW_2 = \frac{1}{2}(200 + 100)(15) = 2250\text{ J}
  4. W=3000+2250=5250 JW = 3000 + 2250 = 5250\text{ J}, so the answer is (b).
Report a mistake

More questions on Work by a Variable Force