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MHT CET 2026 (18 Apr, Shift 2) · Reflection, Superposition & Interference

Reflection, Superposition & Interference question from MHT CET 2026 (18 Apr, Shift 2)

Q2MHT CET 2026 · 18 APR · SHIFT 2Easy

Reflection, Superposition & Interference

A person standing between two parallel cliffs fires a gun and hears two echoes, first echo after 1 second and second echo after 3 second. The distance between the two cliffs is (The velocity of sound =330= 330 m/s)

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Answer: (b)

  1. d1=vt12=330×12=165 md_1 = \frac{v t_1}{2} = \frac{330 \times 1}{2} = 165\text{ m}, d2=330×32=495 md_2 = \frac{330 \times 3}{2} = 495\text{ m}
  2. Separation =165+495=660 m= 165 + 495 = 660\text{ m}
  3. So the answer is (b) 660 m.
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