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JEE Main 2021 (26 Feb, Shift 1) · Apparent Weight & Lift

Apparent Weight & Lift question from JEE Main 2021 (26 Feb, Shift 1)

Q14JEE Main 2021 · 26 FEB · SHIFT 1Easy

Apparent Weight & Lift

A person standing on a spring balance inside a stationary lift measures 60 kg. The weight of that person if the lift descends with uniform downward acceleration of 1.8 m/s2 will be ______________ N. [g = 10 m/s2]

Numerical answer type. Work it out, then open the answer.

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Answer: 492

Mass $m = 60$ kg. Lift descending with $a$ : $N = m(g - a)$ .
$N = 60 \times (10 - 1.8) = 60 \times 8.2$
$N = 492$ N

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