A person travelling on a straight line moves with a uniform velocity v₁ for a distance x and with a uniform velocity v₂ for the next 3/2x distance. The average velocity in this motion is 50/7 m/s. If v₁ is 5 m/s then v₂ = __________ m/s. Numerical answer type. Work it out, then open the answer.

Answer: 10. Total distance = x + 3/2x = 5x/2; total time = x/5 + (3x)/(2v₂). (5x/2)/(x/5 + 3x/(2v₂)) = 50/7 ⇒ 1/5 + 3/2v₂ = 5/2 × 7/50 = 0.35 3/2v₂ = 0.15 ⇒ v₂ = 10 So v₂ = 10 m/s.

A person travelling on a straight line moves with a uniform velocity… | JEE Main 2025 (2 Apr, Shift 1)

Q5JEE Main 2025 · 2 APR · SHIFT 1Easy

Distance, Displacement & Average Speed

A person travelling on a straight line moves with a uniform velocity $v_1$ for a distance $x$ and with a uniform velocity $v_2$ for the next $\frac{3}{2}x$ distance. The average velocity in this motion is $\frac{50}{7}\text{ m/s}$ . If $v_1$ is $5\text{ m/s}$ then $v_2 =$ __________ $\text{m/s}$ .

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 10

Total distance $= x + \frac{3}{2}x = \frac{5x}{2}$ ; total time $= \frac{x}{5} + \frac{3x}{2v_2}$ .
$\frac{5x/2}{x/5 + 3x/(2v_2)} = \frac{50}{7} \Rightarrow \frac{1}{5} + \frac{3}{2v_2} = \frac{5}{2} \times \frac{7}{50} = 0.35$
$\frac{3}{2v_2} = 0.15 \Rightarrow v_2 = 10$
So $v_2 = 10$ m/s.

Report a mistake

Distance, Displacement & Average Speed question from JEE Main 2025 (2 Apr, Shift 1)

More questions on Distance, Displacement & Average Speed