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JEE Main 2023 (10 Apr, Shift 2) · Distance, Displacement & Average Speed

Distance, Displacement & Average Speed question from JEE Main 2023 (10 Apr, Shift 2)

Q10JEE Main 2023 · 10 APR · SHIFT 2Easy

Distance, Displacement & Average Speed

A person travels xx distance with velocity v1v_1 and then xx distance with velocity v2v_2 in the same direction. The average velocity of the person is vv, then the relation between v,v1v, v_1 and v2v_2 will be.

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Answer: (d)

  1. Same direction, so displacement =2x= 2x and time =xv1+xv2= \frac{x}{v_1} + \frac{x}{v_2}.
  2. v=2xx/v1+x/v2⇒2v=1v1+1v2v = \frac{2x}{x/v_1 + x/v_2} \Rightarrow \frac{2}{v} = \frac{1}{v_1} + \frac{1}{v_2}
  3. So the answer is (d).
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