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JEE Main 2016 (10 Apr, Shift 1) · Photoelectric Effect: Einstein's Equation

Photoelectric Effect: Einstein's Equation question from JEE Main 2016 (10 Apr, Shift 1)

Q142JEE Main 2016 · 10 APR · SHIFT 1Medium

Photoelectric Effect: Einstein's Equation

A photoelectric surface is illuminated successively by monochromatic light of wavelengths λ\lambda and λ2.\frac{\lambda}{2}. If the maximum kinetic energy of the emitted photoelectrons in the second case is 3 times that in the first case, the work function of the surface is:

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Answer: (b)

  1. K=hcλ−ϕK = \frac{hc}{\lambda} - \phi; write A=hcλA = \frac{hc}{\lambda}.
  2. First: K1=A−ϕK_1 = A - \phi; second (λ/2\lambda/2): K2=2A−ϕK_2 = 2A - \phi
  3. 2A−ϕ=3(A−ϕ)⇒2ϕ=A2A - \phi = 3(A - \phi) \Rightarrow 2\phi = A
  4. So the answer is (b) ϕ=hc2λ\phi = \frac{hc}{2\lambda}.
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