A photon and an electron (mass m) have the same energy E. The ratio ( λ photon /λ electron) of their de Broglie wavelengths is: ( c is the speed of light) (a) c√(2m/E) (b) 1/c√(E/2m) (c) √(E/2m) (d) c√(2mE)

Answer: (a). λph = hc/E, λe = (h)/(√(2mE)). λphλe = (c√(2mE))/(E) = c√(2m/E) So the answer is (a).

A photon and an electron (mass m) have the same energy E. The ratio (… | NEET 2025

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Matter Waves: de Broglie Wavelength

A photon and an electron (mass $m$ ) have the same energy $E$ . The ratio ( $\lambda$ photon $/\lambda$ electron) of their de Broglie wavelengths is: ( $c$ is the speed of light)

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Answer: (a)

$\lambda_{ph} = \dfrac{hc}{E}$ , $\lambda_e = \dfrac{h}{\sqrt{2mE}}$ .
$\dfrac{\lambda_{ph}}{\lambda_e} = \dfrac{c\sqrt{2mE}}{E} = c\sqrt{\dfrac{2m}{E}}$
So the answer is (a).

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