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MHT CET 2026 (12 May, Shift 1) · Photoelectric Effect: Einstein's Equation

Photoelectric Effect: Einstein's Equation question from MHT CET 2026 (12 May, Shift 1)

Q29MHT CET 2026 · 12 MAY · SHIFT 1Difficult

Photoelectric Effect: Einstein's Equation

A photon of energy 1010 units ejects a photo-electron from a metal surface whose work function is Φ0\Phi_0. If an electron(e) having maximum kinetic energy enters into a uniform magnetic field of induction(B) in a direction perpendicular to the field and describes a circular path of radius R, then radius R is {m=m =mass of electron}

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Answer: (c)

  1. Kmax=10−Φ0K_{max} = 10 - \Phi_0, and momentum p=2mKmaxp = \sqrt{2mK_{max}}.
  2. In the field evB=mv2R⇒R=peBevB = \frac{mv^2}{R} \Rightarrow R = \frac{p}{eB}
  3. So the answer is (c) R=2m(10−Φ0)eBR = \frac{\sqrt{2m(10 - \Phi_0)}}{eB}.
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