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MHT CET 2026 (19 May, Shift 2) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from MHT CET 2026 (19 May, Shift 2)

Q4MHT CET 2026 · 19 MAY · SHIFT 2Easy

Organ Pipes & Resonance Tube

A pipe open at both ends has a frequency $f$ in air. The pipe is dipped vertically in water, so that its $(1/3)$ part of its length is in water. The fundamental frequency of the air column is now $xf$ , the value of $x$ is

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Answer: (b)

In air (open pipe): $f=\frac{v}{2L}$ .
With $\frac{1}{3}$ in water it becomes a closed pipe of length $\frac{2L}{3}$ : $f'=\frac{v}{4\cdot\frac{2L}{3}}=\frac{3v}{8L}$ .
$f'=\frac{3}{4}f$ , so $x=\frac{3}{4}$ : answer (b).

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