Physics Circle home Student Login

Home›Chapters›Wave Motion PYQs›Organ Pipes & Resonance Tube›Question 45

MHT CET 2025 (21 Apr, Shift 1) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from MHT CET 2025 (21 Apr, Shift 1)

Q45MHT CET 2025 · 21 APR · SHIFT 1Difficult

Organ Pipes & Resonance Tube

A pipe open at both ends of length 1.5 m is dipped in water at one end such that 22nd overtone of vibrating air column is resonating with a tuning fork of frequency 330 Hz. The length of the pipe immersed in water is (Speed of sound in air =330 m/s= 330\text{ m/s}) (Neglect end correction)

Show answer and solution

Answer: (d)

  1. Dipped in water, the pipe acts as a closed pipe of air length ll
  2. 2nd overtone of closed pipe = 5th harmonic: f=5v4lf = \frac{5v}{4l}
  3. 330=5×3304l⇒l=1.25 m330 = \frac{5 \times 330}{4l} \Rightarrow l = 1.25\text{ m}
  4. Immersed length =1.5−1.25=0.25 m= 1.5 - 1.25 = 0.25\text{ m}
  5. So the answer is (d) 0.25 m.
Report a mistake

More questions on Organ Pipes & Resonance Tube