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MHT CET 2026 (15 Apr, Shift 1) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from MHT CET 2026 (15 Apr, Shift 1)

Q25MHT CET 2026 · 15 APR · SHIFT 1Difficult

Organ Pipes & Resonance Tube

A Pipe open at one end has length 0.80.8 m. At the open end of the tube a string 0.50.5 m long is vibrating in its first overtone and resonates with fundamental frequency of pipe. If tension in the string is 5050 N, the mass of string is (Neglect end correction) (Speed of sound =320= 320 m/s)

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Answer: (c)

  1. Pipe (closed at one end) fundamental: f=v4L=3204×0.8=100 Hzf = \frac{v}{4L} = \frac{320}{4 \times 0.8} = 100\text{ Hz}
  2. String first overtone (2nd harmonic): f=22lTμ=10.550μf = \frac{2}{2l}\sqrt{\frac{T}{\mu}} = \frac{1}{0.5}\sqrt{\frac{50}{\mu}}
  3. 250μ=100⇒μ=502500=0.02 kg/m2\sqrt{\frac{50}{\mu}} = 100 \Rightarrow \mu = \frac{50}{2500} = 0.02\text{ kg/m}
  4. Mass =μl=0.02×0.5=0.01 kg=10 g= \mu l = 0.02 \times 0.5 = 0.01\text{ kg} = 10\text{ g}
  5. So the answer is (c) 10 gram.
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