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JEE Main 2020 (2 Sep, Shift 1) · Energy Density & Intensity

Energy Density & Intensity question from JEE Main 2020 (2 Sep, Shift 1)

Q26JEE Main 2020 · 2 SEP · SHIFT 1Medium

Energy Density & Intensity

A plane electromagnetic wave, has

frequency of 2.0 ×\times 1010 Hz and its energy density is 1.02 ×\times 10–8 J/m3 in vacuum. The amplitude of the magnetic field of the wave is close to

( 14πε0=9×109Nm2C2\frac{1}{4\pi\varepsilon_0} = 9 \times 10^{9} \frac{Nm^2}{C^2} and speed of light

= 3 ×\times 108 ms–1)

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Answer: (c)

  1. Average energy density u=B022μ0⇒B0=2μ0uu = \dfrac{B_0^2}{2\mu_0} \Rightarrow B_0 = \sqrt{2\mu_0 u}
  2. μ0=1ε0c2=4π×9×1099×1016=4π×10−7\mu_0 = \dfrac{1}{\varepsilon_0 c^2} = \dfrac{4\pi \times 9 \times 10^{9}}{9 \times 10^{16}} = 4\pi \times 10^{-7}
  3. B0=2×4π×10−7×1.02×10−8=2.56×10−14=1.6×10−7B_0 = \sqrt{2 \times 4\pi \times 10^{-7} \times 1.02 \times 10^{-8}} = \sqrt{2.56 \times 10^{-14}} = 1.6 \times 10^{-7} T
  4. So the answer is (c) 160 nT.
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