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JEE Main 2019 (12 Apr, Shift 2) · Nature of EM Waves & Wave Equation

Nature of EM Waves & Wave Equation question from JEE Main 2019 (12 Apr, Shift 2)

Q65JEE Main 2019 · 12 APR · SHIFT 2Medium

Nature of EM Waves & Wave Equation

A plane electromagnetic wave having a frequency v = 23.9 GHz propagates along the positive z- direction in free space. The peak value of the Electric Field is 60 V/m. Which among the following is the acceptable magnetic field component in the electromagnetic wave?

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Answer: (d)

  1. ω=2π×23.9×109≈1.5×1011\omega = 2\pi\times23.9\times10^{9} \approx 1.5\times10^{11} rad/s, k=ω/c=0.5×103k = \omega/c = 0.5\times10^{3} m−1^{-1}.
  2. B0=603×108=2×10−7B_0 = \dfrac{60}{3\times10^{8}} = 2\times10^{-7} T.
  3. Travel along +z+z needs phase (kz−ωt)(kz - \omega t) and B⃗⊥z^\vec B\perp\hat z; i^\hat i is fine.
  4. So the answer is (d) 2×10−7sin⁡(0.5×103z−1.5×1011t)i^2\times10^{-7}\sin(0.5\times10^{3}z - 1.5\times10^{11}t)\hat i.
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