A plane electromagnetic wave propagating in free space has amplitude of electric field of 900 N/C. The amplitude of magnetic field will be:__________ (a) 9 (b) 27 (c) 3 (d) 270 GT

Answer: (c). B₀ = E₀/c. B₀ = 9003× 10⁸ = 3× 10⁻⁶ T = 3. So the answer is (c).

A plane electromagnetic wave propagating in free space has amplitude… | JEE Main 2022 (30 Jul, Shift 2)

Q30JEE Main 2022 · 30 JUL · SHIFT 2Easy

Nature of EM Waves & Wave Equation

A plane electromagnetic wave propagating in free space has amplitude of electric field of $900\ \frac{\text{N}}{\text{C}}$ . The amplitude of magnetic field will be :__________

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Answer: (c)

$B_0 = \frac{E_0}{c}$ .
$B_0 = \frac{900}{3\times 10^{8}} = 3\times 10^{-6}\ \text{T} = 3\ \mu\text{T}$ .
So the answer is (c).

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