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JEE Main 2022 (24 Jun, Shift 1) · Speed of EM Waves in a Medium

Speed of EM Waves in a Medium question from JEE Main 2022 (24 Jun, Shift 1)

Q15JEE Main 2022 · 24 JUN · SHIFT 1Difficult

Speed of EM Waves in a Medium

A plane electromagnetic wave travels in a medium of relative permeability 1.61 and relative permittivity 6.44. If magnitude of magnetic intensity is 4.5 ×\times 10−-2 Am−1{}^{-1} at a point, what will be the approximate magnitude of electric field intensity at that point?

(Given: Permeability of free space μ\mu0 = 4π×\pi \times 10−-7 NA−2{}^{-2}, speed of light in vacuum c = 3 ×\times 108 ms−1{}^{-1})

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Answer: (c)

  1. EH=με=μ0ε0μrεr\dfrac{E}{H} = \sqrt{\dfrac{\mu}{\varepsilon}} = \sqrt{\dfrac{\mu_0}{\varepsilon_0}}\sqrt{\dfrac{\mu_r}{\varepsilon_r}}, with μ0/ε0=μ0c=120π≈377 Ω\sqrt{\mu_0/\varepsilon_0} = \mu_0 c = 120\pi \approx 377\ \Omega
  2. 1.616.44=0.25=0.5⇒E/H=60π≈188.5 Ω\sqrt{\dfrac{1.61}{6.44}} = \sqrt{0.25} = 0.5 \Rightarrow E/H = 60\pi \approx 188.5\ \Omega
  3. E=188.5×4.5×10−2≈8.48E = 188.5 \times 4.5 \times 10^{-2} \approx 8.48 V/m
  4. So the answer is (c) 8.48 V m−1^{-1}.
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