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JEE Main 2024 (1 Feb, Shift 1) · Applications of Bernoulli's Theorem

Applications of Bernoulli's Theorem question from JEE Main 2024 (1 Feb, Shift 1)

Q2JEE Main 2024 · 1 FEB · SHIFT 1Medium

Applications of Bernoulli's Theorem

A plane is in level flight at constant speed and each of its two wings has an area of 40 m240\text{ m}^2. If the speed of the air is 180 km/h180\text{ km/h} over the lower wing surface and 252 km/h252\text{ km/h} over the upper wing surface, the mass of the plane is ___________ kg.

(Take air density to be 1 kg m−31\text{ kg m}^{-3} and g=10 ms−2g = 10\text{ ms}^{-2})

Numerical answer type. Work it out, then open the answer.

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Answer: 9600

  1. 180 km/h=50 m/s180\text{ km/h} = 50\text{ m/s}, 252 km/h=70 m/s252\text{ km/h} = 70\text{ m/s}
  2. ΔP=12ρ(vu2−vl2)=12(1)(4900−2500)=1200 Pa\Delta P = \frac{1}{2}\rho(v_u^2 - v_l^2) = \frac{1}{2}(1)(4900 - 2500) = 1200\text{ Pa}
  3. Lift on both wings: F=ΔP×2A=1200×80=96000 NF = \Delta P \times 2A = 1200 \times 80 = 96000\text{ N}
  4. mg=F⇒m=9600010=9600 kgmg = F \Rightarrow m = \frac{96000}{10} = 9600\text{ kg}
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