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JEE Main 2024 (8 Apr, Shift 2) · Progressive Wave Equation

Progressive Wave Equation question from JEE Main 2024 (8 Apr, Shift 2)

Q37JEE Main 2024 · 8 APR · SHIFT 2Easy

Progressive Wave Equation

A plane progressive wave is given by y=2cos⁡2π(330t−x)my = 2\cos 2\pi(330t - x)\text{m}. The frequency of the wave is:

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Answer: (c)

  1. y=2cos⁡(2π⋅330 t−2πx)y = 2\cos(2\pi \cdot 330\, t - 2\pi x), so ω=2π×330\omega = 2\pi \times 330.
  2. f=ω2π=330 Hzf = \dfrac{\omega}{2\pi} = 330\text{ Hz}
  3. So the answer is (c) 330 Hz330\text{ Hz}.
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