A planet having mass 9Me and radius 4Re, where Me and Re are mass and radius of earth respectively, has escape velocity in km/s given by: (Given escape velocity on earth Ve = 11.2 × 10³ m/s) (a) 33.6 (b) 11.2 (c) 16.8 (d) 67.2

Answer: (c). ve ∝ √(M/R) vp = 11.2√(9/4) = 11.2 × 1.5 = 16.8 km/s So the answer is (c) 16.8.

A planet having mass 9Me and radius 4Re, where Me and Re are mass and… | JEE Main 2023 (13 Apr, Shift 1)

Q26JEE Main 2023 · 13 APR · SHIFT 1Easy

Escape Velocity

A planet having mass $9M_e$ and radius $4R_e$ , where $M_e$ and $R_e$ are mass and radius of earth respectively, has escape velocity in $\text{km/s}$ given by:

(Given escape velocity on earth $V_e = 11.2 \times 10^{3}\text{ m/s}$ )

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Answer: (c)

$v_e \propto \sqrt{\frac{M}{R}}$
$v_p = 11.2\sqrt{\frac{9}{4}} = 11.2 \times 1.5 = 16.8$ km/s
So the answer is (c) 16.8.

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Escape Velocity question from JEE Main 2023 (13 Apr, Shift 1)

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