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JEE Main 2024 (29 Jan, Shift 2) · Kepler's Laws & Planetary Motion

Kepler's Laws & Planetary Motion question from JEE Main 2024 (29 Jan, Shift 2)

Q6JEE Main 2024 · 29 JAN · SHIFT 2Easy

Kepler's Laws & Planetary Motion

A planet takes 200 days to complete one revolution around the Sun. If the distance of the planet from Sun is reduced to one fourth of the original distance, how many days will it take to complete one revolution:

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Answer: (d)

  1. Kepler's third law: T∝r3/2T \propto r^{3/2}.
  2. T′=200×(14)3/2=200×18=25 daysT' = 200 \times \left(\tfrac14\right)^{3/2} = 200 \times \tfrac18 = 25\text{ days}
  3. So the answer is (d) 25.
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