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NEET 2015 (AIPMT) · Friction on an Incline

Friction on an Incline question from NEET 2015 (AIPMT)

Q26NEET 2015 · AIPMTMedium

Friction on an Incline

A plank with a box on it at one end is gradually raised about the other end. As the angle of inclination with the horizontal reaches 30°, the box starts to slip and slides 4.0 m down the plank in 4.0 s.

Figure

The coefficients of static and kinetic friction between the box and the plank will be, respectively

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Answer: (d)

  1. Slipping starts at 30∘30^\circ: μs=tan⁡30∘=0.577≈0.6\mu_s = \tan 30^\circ = 0.577 \approx 0.6.
  2. From rest: 4=12a(4)2⇒a=0.5 m/s24 = \tfrac{1}{2}a(4)^2 \Rightarrow a = 0.5\text{ m/s}^2.
  3. a=g(sin⁡30∘−μkcos⁡30∘)⇒0.5=10(0.5−0.866μk)a = g(\sin 30^\circ - \mu_k\cos 30^\circ) \Rightarrow 0.5 = 10(0.5 - 0.866\mu_k)
  4. μk=0.450.866≈0.5\mu_k = \dfrac{0.45}{0.866} \approx 0.5
  5. So the answer is (d) 0.6 and 0.5.
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