A player caught a cricket ball of mass 150 g moving at a speed of 20 m/s. If the catching process is completed in 0.1 s, the magnitude of force exerted by the ball on the hand of the player is: (a) 150 N (b) 3 N (c) 30 N (d) 300 N

Answer: (c). F = (Δ p)/(Δ t) = mv/t (the ball comes to rest). F = (0.15 × 20)/(0.1) = 30 N So the answer is (c) 30 N.

A player caught a cricket ball of mass 150 g moving at a speed of 20… | JEE Main 2024 (8 Apr, Shift 1)

Q9JEE Main 2024 · 8 APR · SHIFT 1Easy

Impulse & Momentum Conservation

A player caught a cricket ball of mass $150\text{ g}$ moving at a speed of $20\text{ m/s}$ . If the catching process is completed in $0.1\text{ s}$ , the magnitude of force exerted by the ball on the hand of the player is:

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Answer: (c)

$F = \frac{\Delta p}{\Delta t} = \frac{mv}{t}$ (the ball comes to rest).
$F = \frac{0.15 \times 20}{0.1} = 30\text{ N}$
So the answer is (c) 30 N.

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