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JEE Main 2023 (29 Jan, Shift 2) · Electrostatic Potential Energy

Electrostatic Potential Energy question from JEE Main 2023 (29 Jan, Shift 2)

Q37JEE Main 2023 · 29 JAN · SHIFT 2Easy

Electrostatic Potential Energy

A point charge 2×10−2 C2 \times 10^{-2}\text{ C} is moved from P to S in a uniform electric field of 30 N C−130\text{ N C}^{-1} directed along positive x-axis. If coordinates of P and S are (1, 2, 0) m and (0, 0, 0) m respectively, the work done by electric field will be

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Answer: (d)

  1. Work by field =qE Δx= qE\,\Delta x (field along xx only).
  2. Δx=0−1=−1\Delta x = 0 - 1 = -1 m
  3. W=2×10−2×30×(−1)=−0.6W = 2\times10^{-2} \times 30 \times (-1) = -0.6 J =−600= -600 mJ
  4. So the answer is (d) −600-600 mJ.
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