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JEE Main 2021 (24 Feb, Shift 2) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from JEE Main 2021 (24 Feb, Shift 2)

Q87JEE Main 2021 · 24 FEB · SHIFT 2Medium

Electric Flux & Gauss's Law

A point charge of +12 $\mu$ C is at a distance 6 cm vertically above the centre of a square of side 12 cm as shown in figure. The magnitude of the electric flux through the square will be __________ $\times$ 103 Nm2/C.

Numerical answer type. Work it out, then open the answer.

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Answer: 226

Charge at height $6$ cm $= \frac{a}{2}$ above the centre of a square of side $a = 12$ cm: the square is one face of a cube with $q$ at its centre.
$\phi = \frac{q}{6\varepsilon_0} = \frac{12\times10^{-6}}{6\times8.85\times10^{-12}}$
$\phi = 2.26\times10^{5} = 226\times10^{3}$ N m $^2$ /C.

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