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JEE Main 2023 (29 Jan, Shift 1) · Electric Charge & Coulomb's Law

Electric Charge & Coulomb's Law question from JEE Main 2023 (29 Jan, Shift 1)

Q43JEE Main 2023 · 29 JAN · SHIFT 1Medium

Electric Charge & Coulomb's Law

A point charge $q_1 = 4q_0$ is placed at origin. Another point charge $q_2 = -q_0$ is placed at $x = 12$ cm. Charge of proton is $q_0$ . The proton is placed on $x$ axis so that the electrostatic force on the proton is zero. In this situation, the position of the proton from the origin is ___________ cm.

Numerical answer type. Work it out, then open the answer.

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Answer: 24

Zero force point lies beyond the smaller charge $q_2$ , at $x > 12$ cm.
$\dfrac{4q_0}{x^2} = \dfrac{q_0}{(x - 12)^2} \Rightarrow \dfrac{x}{x - 12} = 2$
$x = 24\text{ cm}$ .

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