Electric Dipole question from JEE Main 2019 (12 Apr, Shift 1)

Answer: (d)

1. The y-axis is the equatorial line of a dipole along the x-axis.
2. On the equatorial line $\theta = 90^\circ$, so $V = \frac{p\cos 90^\circ}{4\pi\epsilon_0 d^2} = 0$.
3. Equatorial field is opposite to $\vec{p}$: $\vec{E} = \frac{-\vec{p}}{4\pi\epsilon_0 d^3}$.
4. So the answer is (d) $0, \frac{-\vec{p}}{4\pi\epsilon_0 d^3}$.