Physics Circle home Student Login

Home›Chapters›Thermodynamics PYQs›Thermodynamic Processes›Question 92

MHT CET 2025 (23 Apr, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2025 (23 Apr, Shift 2)

Q92MHT CET 2025 · 23 APR · SHIFT 2Difficult

Thermodynamic Processes

A polyatomic gas at pressure P, having volume ' VV ' expands isothermally to a volume ' 3 V ' and then adiabatically to a volume ' 24 V '. The final pressure of gas is (for moderate temperature changes)

Show answer and solution

Answer: (d)

  1. Polyatomic gas: γ=43\gamma = \frac{4}{3}.
  2. Isothermal V→3VV \to 3V: P1=P3P_1 = \frac{P}{3}.
  3. Adiabatic 3V→24V3V \to 24V (ratio 8): P2=P3(18)4/3=P3×116P_2 = \frac{P}{3}\left(\frac{1}{8}\right)^{4/3} = \frac{P}{3} \times \frac{1}{16}
  4. P2=P48P_2 = \frac{P}{48}, so the answer is (d).
Report a mistake

More questions on Thermodynamic Processes