A polyatomic gas is compressed to (1/8) th of its volume adiabatically. If its initial pressure is P₀, its new pressure will be [Given, (Cp)/(Cv) = 4/3 ] (a) 6P₀ (b) 2P₀ (c) 8P₀ (d) 16P₀

Answer: (d). Adiabatic: P₂ = P₀((V₁)/(V₂))γ with γ = 4/3. P₂ = P₀ · 84/3 = P₀ · 2⁴ = 16P₀ So the answer is (d) 16P₀.

A polyatomic gas is compressed to (1/8) th of its volume… | MHT CET 2025 (23 Apr, Shift 1)

Q82MHT CET 2025 · 23 APR · SHIFT 1Medium

Thermodynamic Processes

A polyatomic gas is compressed to $\left(\frac{1}{8}\right)$ th of its volume adiabatically. If its initial pressure is $P_0$ , its new pressure will be [Given, $\frac{C_p}{C_v} = \frac{4}{3}$ ]

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Answer: (d)

Adiabatic: $P_2 = P_0\left(\frac{V_1}{V_2}\right)^\gamma$ with $\gamma = \frac{4}{3}$ .
$P_2 = P_0 \cdot 8^{4/3} = P_0 \cdot 2^4 = 16P_0$
So the answer is (d) $16P_0$ .

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