A positively charged particle moving due East enters a region of uniform magnetic field directed vertically upwards. This particle will (a) move in a circular path with a decreased speed (b) move in a circular path with a uniform speed (c) get deflected in vertically upward direction (d) move in circular path with an increased speed

Answer: (b). v (East) is perpendicular to B (up), so F = qvB acts perpendicular to v in the horizontal plane. A force always perpendicular to velocity does no work, so speed stays constant and the path is a circle. So the answer is (b) circular path with uniform speed.

A positively charged particle moving due East enters a region of… | NEET 1997 (AIPMT)

Q129NEET 1997 · AIPMTEasy

Moving Charge in a Magnetic Field

A positively charged particle moving due East enters a region of uniform magnetic field directed vertically upwards. This particle will

Show answer and solution

Answer: (b)

$\vec v$ (East) is perpendicular to $\vec B$ (up), so $F = qvB$ acts perpendicular to $\vec v$ in the horizontal plane.
A force always perpendicular to velocity does no work, so speed stays constant and the path is a circle.
So the answer is (b) circular path with uniform speed.

Report a mistake

Moving Charge in a Magnetic Field question from NEET 1997 (AIPMT)

More questions on Moving Charge in a Magnetic Field