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JEE Main 2024 (8 Apr, Shift 2) · Special Purpose Diodes

Special Purpose Diodes question from JEE Main 2024 (8 Apr, Shift 2)

Q37JEE Main 2024 · 8 APR · SHIFT 2Difficult

Special Purpose Diodes

A potential divider circuit is connected with a dc source of 20 V20\text{ V}, a light emitting diode of glow in voltage 1.8 V1.8\text{ V} and a zener diode of breakdown voltage of 3.2 V3.2\text{ V}. The length (PR) of the resistive wire is 20 cm20\text{ cm}. The minimum length of PQ to just glow the LED is _________ cm\text{cm}.

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Numerical answer type. Work it out, then open the answer.

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Answer: 5

  1. The LED is forward biased and the Zener is reverse biased in series between P and Q.
  2. To make the LED glow: VPQ≥1.8+3.2=5V_{PQ} \geq 1.8 + 3.2 = 5 V.
  3. Along the uniform wire, potential drop per cm =20 V20 cm=1= \dfrac{20\text{ V}}{20\text{ cm}} = 1 V/cm.
  4. PQmin=5 V1 V/cm=5PQ_{min} = \dfrac{5\text{ V}}{1\text{ V/cm}} = 5 cm
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