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MHT CET 2020 (16 Oct, Shift 1) · Potentiometer

Potentiometer question from MHT CET 2020 (16 Oct, Shift 1)

Q64MHT CET 2020 · 16 OCT · SHIFT 1Easy

Potentiometer

A potentiometer wire is $4\text{ m}$ long and potential difference of $3\text{ V}$ is maintained between the ends. The emf of the cell, which balances against a length of $100\text{ cm}$ of the potentiometer wire is

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Answer: (d)

$k = \frac{3}{4} = 0.75\ \text{V/m}$ .
$E = k l = 0.75 \times 1 = 0.75\ \text{V}$ .
So the answer is (d) 0.75 V.

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