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MHT CET 2026 (15 Apr, Shift 2) · Potentiometer

Potentiometer question from MHT CET 2026 (15 Apr, Shift 2)

Q4MHT CET 2026 · 15 APR · SHIFT 2Easy

Potentiometer

A potentiometer wire is 4m long and potential difference of 2V is maintained between the ends. The e.m.f. of the cell which balances against a length of 80 cm of the potentiometer wire is

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Answer: (c)

Potential gradient $k = \dfrac{V}{L} = \dfrac{2}{4} = 0.5\text{ V/m}$ .
$E = k\,l = \dfrac{2}{4} \times 0.8$ .
$E = 0.40\text{ V}$ . So the answer is (c) $0.40$ V.

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