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JEE Main 2022 (24 Jun, Shift 2) · Potentiometer

Potentiometer question from JEE Main 2022 (24 Jun, Shift 2)

Q51JEE Main 2022 · 24 JUN · SHIFT 2Medium

Potentiometer

A potentiometer wire of length 10 m and resistance 20 Ω\Omega is connected in series with a 25 V battery and an external resistance 30 Ω\Omega. A cell of emf E in secondary circuit is balanced by 250 cm long potentiometer wire. The value of E (in volt) is x10\frac{x}{10}. The value of x is __________.

Numerical answer type. Work it out, then open the answer.

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Answer: 25

  1. I=2520+30=0.5 AI = \frac{25}{20 + 30} = 0.5\ \text{A}, p.d. across wire =0.5×20=10 V= 0.5 \times 20 = 10\ \text{V}.
  2. k=1010=1 V/mk = \frac{10}{10} = 1\ \text{V/m}.
  3. E=1×2.5=2.5 V=2510 VE = 1 \times 2.5 = 2.5\ \text{V} = \frac{25}{10}\ \text{V}, so x=25x = 25.
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