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JEE Main 2018 (16 Apr, Shift 1) · AC Generator & Transformer

AC Generator & Transformer question from JEE Main 2018 (16 Apr, Shift 1)

Q49JEE Main 2018 · 16 APR · SHIFT 1Easy

AC Generator & Transformer

A power transmission line feeds input power at 2300 V to a step down transformer with its primary windings having 4000 turns, giving the output power at 230 V. If the current in the primary of the transformer is 5 A, and its efficiency is 90%, the output current would be;

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Answer: (b)

  1. Pin=VpIp=2300×5=11500 WP_{in} = V_pI_p = 2300 \times 5 = 11500\text{ W}
  2. Pout=0.9×11500=10350 WP_{out} = 0.9 \times 11500 = 10350\text{ W}
  3. Is=10350230=45 AI_s = \dfrac{10350}{230} = 45\text{ A}
  4. So the answer is (b) 45 A.
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