A progressive wave of frequency 400 Hz is travelling with velocity 336 m/s. How far apart are the two points on a wave which are 60° out of phase? (a) 0.12 m (b) 0.14 m (c) 0.21 m (d) 0.28 m

Answer: (b). λ = v/f = (336)/(400) = 0.84 m 60° out of phase means Δ x = (λ)/(6) = 0.84/6 = 0.14 m So the answer is (b) 0.14 m.

A progressive wave of frequency 400 Hz is travelling with velocity… | MHT CET 2025 (19 Apr, Shift 2)

Q31MHT CET 2025 · 19 APR · SHIFT 2Easy

Progressive Wave Equation

A progressive wave of frequency 400 Hz is travelling with velocity $336\text{ m/s}$ . How far apart are the two points on a wave which are $60^\circ$ out of phase?

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Answer: (b)

$\lambda = \frac{v}{f} = \frac{336}{400} = 0.84$ m
$60^\circ$ out of phase means $\Delta x = \frac{\lambda}{6} = \frac{0.84}{6} = 0.14$ m
So the answer is (b) $0.14$ m.

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