A projectile is fired from the surface of the earth with a velocity… | NEET 2014 (AIPMT)

Q29NEET 2014 · AIPMTMedium

Time of Flight, Maximum Height & Range

A projectile is fired from the surface of the earth with a velocity of 5 m s−1 and angle $\theta$ with the horizontal. Another projectile fired from another planet with a velocity of 3 m s−1 at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (in m s ${}^{-2}$ ) is

(Given g = 9.8 m s ${}^{-2}$ )

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Answer: (a)

Identical trajectory at the same angle needs the same $\frac{u^2}{g}$ (range and height both $\propto \frac{u^2}{g}$ ).
$\frac{5^2}{9.8} = \frac{3^2}{g'} \Rightarrow g' = 9.8 \times \frac{9}{25}$
$g' \approx 3.5\text{ m s}^{-2}$
So the answer is (a) 3.5.

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Time of Flight, Maximum Height & Range question from NEET 2014 (AIPMT)

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