A projectile is given an initial velocity of (i + 2j) m/s, where i is along the ground and j is along the vertical. If g = 10 m/s2, the equation of its trajectory is: (a) y = x - 5x2 (b) y = 2x - 5x2 (c) 4y = 2x - 5x2 (d) 4y = 2x - 25x2

Answer: (b). ux = 1, uy = 2: x = t, y = 2t - 5t² Put t = x: y = 2x - 5x² So the answer is (b).

A projectile is given an initial velocity of (i + 2j) m/s, where i is… | JEE Main 2013

Q7JEE Main 2013Easy

Projectile Basics & Trajectory

A projectile is given an initial velocity of $\left(\hat{i} + 2\hat{j}\right)$ m/s, where $\hat{i}$ is along the ground and $\hat{j}$ is along the vertical. If g = 10 m/s2, the equation of its trajectory is:

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Answer: (b)

$u_x = 1$ , $u_y = 2$ : $x = t$ , $y = 2t - 5t^2$
Put $t = x$ : $y = 2x - 5x^2$
So the answer is (b).

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Projectile Basics & Trajectory question from JEE Main 2013

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