A proton, a neutron, an electron and an α particle have same energy. If λ p, λ n, λ e and λα are the de Broglie's wavelengths of proton, neutron, electron and α particle respectively, then choose the correct relation from the following: (a) λ p = λ n > λ e > λα (b) λα λα (d) λ e = λ p = λ n = λα

Answer: (b). Same energy: λ = (h)/(√(2mK)) ∝ 1/√(m). Masses: me < mp < mn < mα (the neutron is slightly heavier than the proton). So λα < λn < λp < λe, answer (b).

A proton, a neutron, an electron and an α particle have same energy… | JEE Main 2022 (25 Jun, Shift 2)

Q84JEE Main 2022 · 25 JUN · SHIFT 2Easy

Matter Waves: de Broglie Wavelength

A proton, a neutron, an electron and an $\alpha$ particle have same energy. If $\lambda$ p, $\lambda$ n, $\lambda$ e and $\lambda_\alpha$ are the de Broglie's wavelengths of proton, neutron, electron and $\alpha$ particle respectively, then choose the correct relation from the following:

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Answer: (b)

Same energy: $\lambda = \dfrac{h}{\sqrt{2mK}} \propto \dfrac{1}{\sqrt{m}}$ .
Masses: $m_e < m_p < m_n < m_\alpha$ (the neutron is slightly heavier than the proton).
So $\lambda_\alpha < \lambda_n < \lambda_p < \lambda_e$ , answer (b).

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Matter Waves: de Broglie Wavelength question from JEE Main 2022 (25 Jun, Shift 2)

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