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JEE Main 2024 (9 Apr, Shift 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2024 (9 Apr, Shift 1)

Q54JEE Main 2024 · 9 APR · SHIFT 1Easy

Matter Waves: de Broglie Wavelength

A proton, an electron and an alpha particle have the same energies. Their de-Broglie wavelengths will be compared as:

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Answer: (b)

  1. Same kinetic energy: λ=h2mK∝1m\lambda = \dfrac{h}{\sqrt{2mK}} \propto \dfrac{1}{\sqrt{m}}.
  2. Masses: me<mp<mαm_e < m_p < m_\alpha, so λe>λp>λα\lambda_e > \lambda_p > \lambda_\alpha.
  3. So the answer is (b) λα<λp<λe\lambda_\alpha < \lambda_p < \lambda_e.
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