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JEE Main 2024 (9 Apr, Shift 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2024 (9 Apr, Shift 1)

Q54JEE Main 2024 · 9 APR · SHIFT 1Easy

Matter Waves: de Broglie Wavelength

A proton, an electron and an alpha particle have the same energies. Their de-Broglie wavelengths will be compared as:

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Answer: (b)

Same kinetic energy: $\lambda = \dfrac{h}{\sqrt{2mK}} \propto \dfrac{1}{\sqrt{m}}$ .
Masses: $m_e < m_p < m_\alpha$ , so $\lambda_e > \lambda_p > \lambda_\alpha$ .
So the answer is (b) $\lambda_\alpha < \lambda_p < \lambda_e$ .

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