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JEE Main 2024 (8 Apr, Shift 2) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2024 (8 Apr, Shift 2)

Q55JEE Main 2024 · 8 APR · SHIFT 2Easy

Matter Waves: de Broglie Wavelength

A proton and an electron have the same de Broglie wavelength. If $\mathrm{K_p}$ and $\mathrm{K_e}$ be the kinetic energies of proton and electron respectively, then choose the correct relation:

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Answer: (c)

Same $\lambda = \dfrac{h}{p}$ means same momentum $p$ .
$K = \dfrac{p^2}{2m} \propto \dfrac{1}{m}$ ; since $m_p > m_e$ , $K_p < K_e$ .
So the answer is (c) $K_p < K_e$ .

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