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NEET 2019 · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from NEET 2019

Q121NEET 2019Easy

Matter Waves: de Broglie Wavelength

A proton and an α\alpha-particle are accelerated from rest to the same energy. The de Broglie wavelengths λp\lambda_p and λα\lambda_\alpha are in the ratio,

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Answer: (b)

  1. Same kinetic energy KK: λ=h2mK\lambda = \dfrac{h}{\sqrt{2mK}}, so λ∝1m\lambda \propto \dfrac{1}{\sqrt{m}}.
  2. λpλα=mαmp=4=2\dfrac{\lambda_p}{\lambda_\alpha} = \sqrt{\dfrac{m_\alpha}{m_p}} = \sqrt{4} = 2
  3. So the answer is (b) 2:12 : 1.
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