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JEE Main 2004 (AIEEE) · Momentum & Radiation Pressure

Momentum & Radiation Pressure question from JEE Main 2004 (AIEEE)

Q14JEE Main 2004 · AIEEEEasy

Momentum & Radiation Pressure

A radiation of energy EE falls normally on a perfectly reflecting surface. The momentum transferred to the surface is

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Answer: (b)

  1. Incident momentum p=E/cp = E/c
  2. Perfect reflection reverses it: Δp=2E/c\Delta p = 2E/c
  3. So the answer is (b) 2E/c2E/c.
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