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NEET 2015 (AIPMT, Cancelled Paper) · Momentum & Radiation Pressure

Momentum & Radiation Pressure question from NEET 2015 (AIPMT, Cancelled Paper)

Q12NEET 2015 · AIPMT · CANCELLED PAPEREasy

Momentum & Radiation Pressure

A radiation of energy 'E' falls normally on a perfectly reflecting surface. The momentum transferred to the surface is (C = Velocity of light)

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Answer: (d)

Incident momentum $p = \dfrac{E}{C}$
On perfect reflection the momentum reverses: $\Delta p = \dfrac{E}{C} - \left(-\dfrac{E}{C}\right) = \dfrac{2E}{C}$
So the answer is (d) $\dfrac{2E}{C}$ .

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