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MHT CET 2025 (26 Apr, Shift 2) · Law of Radioactive Decay

Law of Radioactive Decay question from MHT CET 2025 (26 Apr, Shift 2)

Q15MHT CET 2025 · 26 APR · SHIFT 2Easy

Law of Radioactive Decay

A radio active element has rate of disintegration 8000 disintegrations per minute at a particular instant. After four minutes it becomes 2000 disintegrations per minute. The decay constant per minute is

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Answer: (c)

  1. RR0=20008000=14\frac{R}{R_0} = \frac{2000}{8000} = \frac{1}{4}, so 2 half-lives in 4 min.
  2. T1/2=2 minT_{1/2} = 2\text{ min}.
  3. λ=ln⁡22=0.5log⁡e2 min−1\lambda = \frac{\ln 2}{2} = 0.5 \log_e 2\ \text{min}^{-1}.
  4. So the answer is (c) 0.5log⁡e20.5 \log_e 2.
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