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NEET 1990 (AIPMT) · Photons: Energy, Momentum & Radiation Pressure

Photons: Energy, Momentum & Radiation Pressure question from NEET 1990 (AIPMT)

Q48NEET 1990 · AIPMTEasy

Photons: Energy, Momentum & Radiation Pressure

A radio transmitter operates at a frequency 880 kHz and a power of 10 kW. The number of photons emitted per second is

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Answer: (a)

  1. E=hν=(6.63×10−34)(880×103)=5.83×10−28 JE = h\nu = (6.63 \times 10^{-34})(880 \times 10^{3}) = 5.83 \times 10^{-28}\text{ J}
  2. n=PE=1045.83×10−28≈1.72×1031 s−1n = \frac{P}{E} = \frac{10^{4}}{5.83 \times 10^{-28}} \approx 1.72 \times 10^{31}\text{ s}^{-1}
  3. So the answer is (a) 1.72×10311.72 \times 10^{31}.
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